[seqfan] Re: A174168
franktaw at netscape.net
franktaw at netscape.net
Tue Oct 25 23:56:17 CEST 2011
Looks like a typo. I believe the correct formula has a(n-3) instead of
the first a(n-2):
a(n)=(a(n-1)*a(n-3)+3*a(n-2)^2)/a(n-4)
Franklin T. Adams-Watters
-----Original Message-----
From: Harvey P. Dale <hpd1 at nyu.edu>
I am fairly certain that the formula for the above sequence is
wrong, but I can't figure out how to generate the terms of the sequence.
Best,
Harvey
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