[seqfan] Re: a partition sequence
William Keith
william.keith at gmail.com
Mon Oct 3 00:09:49 CEST 2011
On Sun, Oct 2, 2011 at 10:22 PM, David Newman <davidsnewman at gmail.com>wrote:
> I'd like someone to check my numbers before I propose this sequence.
>
> Let a(n) be the number of planar partitions whose summands are
> distinct going across rows and have distinct frequencies going down
> columns.
>
You'd better be more precise. I understand this as near as I can to mean
that each row consists of distinct summands, and the list of frequencies of
summands in each column (other than an infinite set of 0s) is a list of
distinct numbers for each summand. However:
3 3
>
There are two 3s in this partition, and the list of frequencies of 3s in
each column is 1 and 1.
So either there's something off with your calculations or I didn't
understand your definition.
William Keith
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