[seqfan] Re: a partition sequence
David Scambler
dscambler at bmm.com
Mon Oct 10 07:40:17 CEST 2011
After finding multiple bugs, I think this might be correct, up to 260 chars, n=44.
1, 1, 2, 3, 5, 9, 14, 21, 32, 47, 67, 98, 136, 199, 277, 387, 537, 745, 1012, 1390, 1860, 2509, 3354,
4480, 5912, 7830, 10267, 13471, 17553, 22857, 29588, 38313, 49301, 63391, 81184, 103803, 132228,
168196, 213259, 269898, 340752, 429284, 539581, 676960, 847417
Can anyone else compute a few terms to check it?
Dave
David Newman davidsnewman at gmail.com
Sun Oct 2 23:22:11 CEST 2011
I'd like someone to check my numbers before I propose this sequence.
Let a(n) be the number of planar partitions whose summands are
distinct going across rows and have distinct frequencies going down columns.
I get a(1)=1, a(2)=2, a(3)=3, a(4)=5, a(5)=9, a(6)=14, a(7)=21 for the
values that I've computed by hand.
For example the allowed partitions of 6 are:
...
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