[seqfan] Re: A174168

[franktaw at netscape.net]

Looks like a typo. I believe the correct formula has a(n-3) instead of 
the first a(n-2):

a(n)=(a(n-1)*a(n-3)+3*a(n-2)^2)/a(n-4)

Franklin T. Adams-Watters

-----Original Message-----
From: Harvey P. Dale <hpd1 at nyu.edu>

	I am fairly certain that the formula for the above sequence is
wrong, but I can't figure out how to generate the terms of the sequence.

	Best,

	Harvey