[seqfan] Re: nth divisor of a number
Benoît Jubin
benoit.jubin at gmail.com
Sun Apr 1 01:49:09 CEST 2012
You're right, David W, one triangular table is enough, and I would
omit the first column. Please, submit this sequence and the "most
likely n-th divisor" sequence, and feel free to add the formulas I
wrote, or to give me the A-number so that I do it. I think Robert
Israel and Charles Greathouse could be mentioned for that sequence.
Anyone has an idea for the asymptotic growth of the "most likely n-th
divisor" sequence?
Benoît
On Sat, Mar 31, 2012 at 11:00 AM, David Wilson <davidwwilson at comcast.net> wrote:
> On 3/31/2012 1:58 AM, Benoît Jubin wrote:
>>
>> And these probabilities are obviously rational numbers, so two OEIS
>> tables will be enough!
>>
> In this case, I almost think one tabular sequence would be enough, to wit
>
> 1
> 0 1
> 0 1 1
> 0 0 2 1
> 0 4 4 3 1
> 0 0 0 4 5 1
>
> &c, with the understanding that the denominator of the nth row is LCM(1, ..,
> n).
>
>
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