[seqfan] Re: Fwd: Formula for A025672
franktaw at netscape.net
franktaw at netscape.net
Mon Feb 20 03:09:08 CET 2012
I am certain it is wrong. The formula (correcting the final k to n) is
for the sequence which concatenates
<n-1,n-2,n-3,...,0,n-1,n-2,n-3,...,0> for each n. A025672 depends on
log(3)/log(8), which is an irrational number, so it does not have this
form. I don't where they diverge, but I would guess it's not much past
the published sequence.
Franklin T. Adams-Watters
-----Original Message-----
From: David Wilson <davidwwilson at comcast.net>
The sender already A025672 the sequence with the following formula.
My intuition says the formula is wrong.
Any takers?
-------- Original Message --------
Subject: Formula for A025672
Dear David W. Wilson,
I am glad to say I found a formula for the sequence A025672 .
A025672(n) = floor((1/4)*ceil(2*sqrt(n))^2)-k
I hope it is useful.
Sincerely,
Mircea Merca,
Department of Informatics,
Constantin Istrati Technical College,
105600 Campina, Romania
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