On 3/31/2012 1:58 AM, Benoît Jubin wrote: > And these probabilities are obviously rational numbers, so two OEIS > tables will be enough! > In this case, I almost think one tabular sequence would be enough, to wit 1 0 1 0 1 1 0 0 2 1 0 4 4 3 1 0 0 0 4 5 1 &c, with the understanding that the denominator of the nth row is LCM(1, .., n).