[seqfan] Re: A016037 alphabetical length steps samples

Robert G. Wilson v rgwv at rgwv.com
Thu May 31 23:38:26 CEST 2012

Et al,


               It has been awhile since I did this and there is no
Mathematica coding to help, I am trying to reconstruct the sequence and
pinpoint the problem. I will post to the sequence the results.


Thank you, Bob.

P.S. Obviously I am still on the list.


From: Neil Sloane [mailto:njasloane at gmail.com] 
Sent: Thursday, May 31, 2012 2:29 PM
To: Sequence Fanatics Discussion list
Cc: rgwv at rgwv.com
Subject: Re: [seqfan] A016037 alphabetical length steps samples


A016037 was submitted by Bob Wilson, rgwv at rgwv.com, who 

used to be a member of this list. Perhaps you should ask him

directly? In fact I will copy this to him.

Bob, can you answer Kevin's questions?


On Wed, May 30, 2012 at 6:54 PM, Kevin Ryde <user42 at zip.com.au> wrote:

In A016037 iterations of taking the length of a number in letters, the
samples show a(72)=4 and a(76)=3, if I count along correctly.

Is that right?  I thought since "seventy two" and "seventy six" have the
same number of starting letters they would both be 4 iterations

   72 -> 10 -> 3 -> 5 -> 4

Some other length=10 samples are 3 too, such as "forty three" a(43)=3.
Is there something subtle I'm missing?  I take it A005589 is the map
iterated, as it refers to A016037 (though there's no reference back).


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