[seqfan] Re: A016037 alphabetical length steps samples
Robert G. Wilson v
rgwv at rgwv.com
Thu May 31 23:38:26 CEST 2012
Et al,
It has been awhile since I did this and there is no
Mathematica coding to help, I am trying to reconstruct the sequence and
pinpoint the problem. I will post to the sequence the results.
Thank you, Bob.
P.S. Obviously I am still on the list.
From: Neil Sloane [mailto:njasloane at gmail.com]
Sent: Thursday, May 31, 2012 2:29 PM
To: Sequence Fanatics Discussion list
Cc: rgwv at rgwv.com
Subject: Re: [seqfan] A016037 alphabetical length steps samples
A016037 was submitted by Bob Wilson, rgwv at rgwv.com, who
used to be a member of this list. Perhaps you should ask him
directly? In fact I will copy this to him.
Bob, can you answer Kevin's questions?
Neil
On Wed, May 30, 2012 at 6:54 PM, Kevin Ryde <user42 at zip.com.au> wrote:
In A016037 iterations of taking the length of a number in letters, the
samples show a(72)=4 and a(76)=3, if I count along correctly.
Is that right? I thought since "seventy two" and "seventy six" have the
same number of starting letters they would both be 4 iterations
72 -> 10 -> 3 -> 5 -> 4
Some other length=10 samples are 3 too, such as "forty three" a(43)=3.
Is there something subtle I'm missing? I take it A005589 is the map
iterated, as it refers to A016037 (though there's no reference back).
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