# [seqfan] Re: Fixing A175155 Numbers n satisfying n^2 + 1 = x^2 y^3

Robert G. Wilson v rgwv at rgwv.com
Fri Nov 16 19:06:35 CET 2012

```SeqFans,

Shouldn't 0 also be in the sequence since it satisfies the criteria?

Bob.

-----Original Message-----
From: SeqFan [mailto:seqfan-bounces at list.seqfan.eu] On Behalf Of Charles
Greathouse
Sent: Friday, November 16, 2012 11:24 AM
To: Sequence Fanatics Discussion list
Subject: [seqfan] Re: Fixing A175155 Numbers n satisfying n^2 + 1 = x^2 y^3

Good catch, Georgi.

I wouldn't add a new sequence, just correct this one. (Unless someone feels
that this would be worthwhile?)

Charles Greathouse
Analyst/Programmer
Case Western Reserve University

On Fri, Nov 16, 2012 at 10:56 AM, Georgi Guninski
<guninski at guninski.com>wrote:

> A175155 Numbers n satisfying n^2 + 1 = x^2 y^3
>
> I am not sure this is entirely correct:
> >This sequence is infinite. The fundamental solution of n^2 + 1 = x^2
> >y^3
> is (n,x,y) = (682,61,5), that mean the Pellian equation n^2 - 125x^2 =
> -1 has the solution (n,x) = (682,61) =(n(1),x(1)). Then, this Pellian
> equation admit an infinity solutions (n(2k+1),x(2k+1))
>
> This indeed is a family of solutions giving the smallest one, but
> there are infinitely many other solutions arising from
> x^2 - k^3 y^2 = -1
>
> In particular n=1459639851109444 is missing from the sequence.
> n^2 + 1 = 17^3 * 79153^2 * 263090369^2
>
> I suggest:
> 1. Adding the missing term and other low hanging fruit from pell eqs
> 2. Indicating that terms might be missing (the sequence contains a
> 22 digit number and I suppose it is infeasible to find all terms up to
> it)
>
> Should I submit another sequence that currently numerically coincides
> with A175155?
>
> Solution x to x^2 - 125 y^2 = -1
>
>
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