[seqfan] Re: A121064

[Neil Sloane]

Ray Opao just replied to my email. Here is what he says:
(start)
Go ahead and make the corrections. I think I checked only numbers up
to 300 and made the wrong assumption that the rest had more letters.
Thanks for informing me of my error.
(end)

So, Hans, please go ahead and correct the entries!
Thanks
Neil

On Sat, Sep 8, 2012 at 8:32 PM, Hans Havermann <gladhobo at teksavvy.com>wrote:

> 0, 0, 0, 4, 4, 6, 6, 3, 13, 22, 25, 15, 3, 12, 9, 18, 18, 9 (offset 0)
>
>
>  maybe the author only looked at values up to 100
>>>
>>
>> That was my first guess and the author's a(11) = 15 and a(12) = 3 are in
>> line with that thought. Unfortunately, there are no a(13) and beyond in
>> that scheme.
>>
>
> I'll take this a step further. The a(10) = 25 would be correct for any
> counts up to and including the numbers 100 - 199. The number 200 adds
> another 10-letter instance to the count making it 26 at this point..
>
> a(10) = 25 is correct only for counts up to and including 100- 199
> a(11) = 15 is correct only for counts up to and including  98- 399
> a(12) =  3 is correct only for counts up to and including  78- 299
> a(13) = 12 is correct only for counts up to and including 610-2999
> a(14) =  9 is correct only for counts up to and including 406- 409
> a(15) = 18 is correct only for counts up to and including 405- 408
> a(16) = 18 is correct only for counts up to and including 408- 439
> a(17) =  9 is correct only for counts up to and including 308- 339
>
> There is a modicum of consistency here: a(10) to a(12), a(14) to a(16);
> but the earlier consistency trumps the later one, so I think it fair to
> conclude that either a(13) to a(17) are superfluous to the author counting
> up to 100 (say) since a(12) makes *that* sequence full or, if it was the
> author's intention to go further, beyond 399 (say), then a(10) to a(12) are
> incorrect, in addition to some of the others. Take your pick.
>
>
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Neil J. A. Sloane, President, OEIS Foundation
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