[seqfan] Re: Next integer ? A new multiple of (d+1)

Eric Angelini Eric.Angelini at kntv.be
Wed Dec 4 14:03:43 CET 2013

Ok, I have my answer now, many thanks to Emmanuel Vanthiegem:

>Hello Seqfans,
>This was fun to imagine:
>Start S with a(n)=1
>Now a(n+1) is always the smallest integer not yet present in S such 
>that a(n+1) is a multiple of (d+1), d being the last digit of a(n):

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