[seqfan] Re: Perhaps interesting sequence

W. Edwin Clark wclark at mail.usf.edu
Sun Dec 1 04:25:38 CET 2013


It seems to me that a(1)  = a(0 mod 0)+1 should be 1 and not 0. This
assumes that 0 mod 0 = 0 which perhaps logical since when n = 0, Z/nZ =
Z/(0) is isomorphic to Z.


On Sat, Nov 30, 2013 at 2:06 PM, Aai <agroeneveld400 at gmail.com> wrote:

> If I'm not wrong this seq is based on a easy index pattern
>
> 0 0  0  0 1 0 1  0  0 1 2 0 1 2  0  0 1 2 3 0 1 2 3  0  0 1 2 3 4 0 1 2 3 4
> ---     -------     -----------     --------------- -------------------
>
> On 30-11-13 17:34, David Wilson wrote:
>
>> Define
>>
>>
>> a(0) = 0; a(n+1) = a(n mod floor(sqrt(n))) + 1;
>>
>>
>> This sequence grows slowly, the first appearance of a(n) = k seems to be
>> at
>> n = A000058(n) - 2.
>>
>>
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>
> --
> Met vriendelijke groet,
> @@i = Arie Groeneveld
>
>
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