[seqfan] Re: Fibonaccit

Lars Blomberg lars.blomberg at visit.se
Sat Feb 16 18:02:56 CET 2013

Hello Hans,

Neither am I a mathematician, but I agree with your reasoning.
(It so happens that I made my calculation and decided to publish it before I 
had read your mail).

-----Ursprungligt meddelande----- 
From: Hans Havermann
Sent: Saturday, February 16, 2013 5:53 PM
To: Sequence Fanatics Discussion list
Subject: [seqfan] Re: Fibonaccit

Lars Blomberg:

> I have found no loop within the first 10^8 terms.

Hey Lars. :)

As a non-mathematician I can't quite formalize a proof, but consider those 
consecutive 18s mentioned in my previous post. A stretch of k 18s will 
generate roughly 2k 9s in the corresponding summed-digits list, which in 
turn generate 2k 18s. Thus the number of consecutive 18s will grow without 
limit and no loops are possible.


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