[seqfan] Re: A012278
franktaw at netscape.net
franktaw at netscape.net
Sun Feb 17 07:55:49 CET 2013
Yes.
Myself, I would probably add the 0.
Franklin T. Adams-Watters
-----Original Message-----
From: israel <israel at math.ubc.ca>
A012278 is entitled
"arctanh(exp(x)*log(x+1))=x+1/2!*x^2+4/3!*x^3+12/4!*x^4+103/5!*x^5...
".
Thus it should be the sequence whose egf is arctanh(exp(x)*log(x+1)).
Except not quite: with an offset given as 0, it starts 1, 1, 4, 12,
103. I
think either the offset should be 1 or the 0'th term should be 0, so
that
A012278[n] should be n! times the coefficient of the x^n term.
Robert Israel
University of British Columbia
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