[seqfan] Re: Fibonaccit
Lars Blomberg
lars.blomberg at visit.se
Sat Feb 16 18:02:56 CET 2013
Hello Hans,
Neither am I a mathematician, but I agree with your reasoning.
(It so happens that I made my calculation and decided to publish it before I
had read your mail).
-----Ursprungligt meddelande-----
From: Hans Havermann
Sent: Saturday, February 16, 2013 5:53 PM
To: Sequence Fanatics Discussion list
Subject: [seqfan] Re: Fibonaccit
Lars Blomberg:
> I have found no loop within the first 10^8 terms.
Hey Lars. :)
As a non-mathematician I can't quite formalize a proof, but consider those
consecutive 18s mentioned in my previous post. A stretch of k 18s will
generate roughly 2k 9s in the corresponding summed-digits list, which in
turn generate 2k 18s. Thus the number of consecutive 18s will grow without
limit and no loops are possible.
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