[seqfan] Call for more digits of 1/(3*5) + 1/(5*7) + 1/(7*11)

mathar mathar at mpia-hd.mpg.de
Tue Jan 22 14:35:35 CET 2013


This is some call to compute additional digits to the
sum 1/(3*5) +1/(5*7) + 1/(7*11)+.. in http://oeis.org/A209329 ,
where the denominators walk through products of adjacent odd primes.

The usual Euler-zeta-methods do not provide much guidance, because the
selection of the two terms in the denominators is not just irregular with
respect to the lower prime but also irregular with respect to the gap
up to the next prime.

On a term-by-term basis, the partial sums of A185380 are upper estimates
of the partial sums of this sum, if we look at 1/(p*(p+2)) as using an
estimator p+2 as a substitute for the next prime after p.
(At the same time, convergence of A185380 proofs that A209329 converges,
and A185380 is itself majored by the sum over 1/p^2, the prime zeta function
at 2, A085548, which is also known to converge.)
Similarly, the partial sums of sum_{odd primes q} 1/(q*(q-2)) =
0.4635423529706636936146055639434089111278372208711.. provide a lower estimate
if we consider q-2 as an estimator for the prime previous to q (and remove
the initial 1/3).
Accurate upper and lower limits A209329 can therefore be
constructed by keeping track of the three partial sums of 1/(q*(q-2)),
1/(prime(j)*prime(j+1)) and 1/(p*(p+2)) and using the known distances
of the partial sums of the two auxiliary sequence to their limits
as upper and lower limits of the remaining distance of this sequence to
its limit. 

So that summarizes what I actually know about that sum.

(Side node: A124012 is even more irregular and converging worse; finding
useful upper and lower estimators for the terms looks much more challenging
there...)

Richard



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