[seqfan] Re: A081458

[Robert G. Wilson v]

Seq.Fans,

	Like Harvey, I find this sequence troubling at many levels.

	First, why is the sequence not sorted.

	Second, no term is present where the exponent of 3 exceed that of 5.

	Therefore, I suggest that to get as close to what is presented, the
follow:

Name: Numbers of the form (3^(2n) + 5^(2m))/2 where m is less than or equal
to n.
data: 1, 13, 17, 313, 317, 353, 7813, 7817, 7853, 8177, 195313, 195317,
195353, 195677, 198593, 4882813, 4882817, 4882853, 4883177, 4886093,
4912337, 122070313, 122070317, 122070353, 122070677, 122073593, 122099837,
122336033, 3051757813, 3051757817, 3051757853, 3051758177, ., .
Mmca: Take[ Union[ Flatten[ Table[ (3^m + 5^n)/2, {n, 0, 14, 2}, {m, 0, n,
2}]]], 32]  

Sincerely, Bob.

-----Original Message-----
From: SeqFan [mailto:seqfan-bounces at list.seqfan.eu] On Behalf Of Harvey P.
Dale
Sent: Tuesday, January 01, 2013 1:27 PM
To: Sequence Fanatics Discussion list
Subject: [seqfan] A081458

	The first formula does not generate the terms of the sequence.
	Happy New Year.
	Best,
	Harvey
 


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