[seqfan] Re: Generalized Erdos-Straus conjecture

T. D. Noe noe at sspectra.com
Tue Jul 16 18:12:17 CEST 2013


See A075248 (number of solutions (x,y,z) to 5/n = 1/x + 1/y + 1/z
satisfying 0 < x < y < z.)

Best regards,

Tony


At 9:43 AM -0400 7/16/13, Allan Wechsler wrote:
>A192787 tells how many ways there are to partition 4/n into three positive
>integer reciprocals. The famous Erdos-Straus conjecture states that for
>n>1, this is always nonzero.
>
>Is there a similar sequence for partitioning 5/n into three reciprocals? If
>I counted right, the answer is no, because I am getting 0, 0, 2, 4, 3, 4,
>4, and OEIS has only one match, and it has a -2 in it. But I could have
>counted wrong.
>
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