[seqfan] Re: Extending erroneous A094333 ?

Jim Nastos nastos at gmail.com
Mon Jul 22 23:41:07 CEST 2013


Tony,
  Is that really enough justification?

  I think I side with Paul Tek's comment here ... that if multiples such as
"2" or "4" or "8" are allowed to be considered concatenations of
"successive numbers" (obviously allowing for trivial concatenations) then
the next multiple of 8 (being 16) should be the 5th term of the existing
sequence.

  Why would trivial concatenations only be allowed for single-digit terms
and not for others?
JN



On Mon, Jul 22, 2013 at 2:20 PM, T. D. Noe <noe at sspectra.com> wrote:

> Perhaps you do not understand the sequence. I think it is correct because
> others have contributed to it.
>
> Best regards,
>
> Tony
>
> At 6:19 PM +0200 7/22/13, Paul Tek wrote:
> >Dear SeqFans,
> >
> >I would like to extend the sequence A094333:
> >  NAME:   a(1) = 1, a(n) = least multiple of a(n-1) which is a
> >concatenation of successive numbers.
> >  DATA:   1, 2, 4, 8, 56, 5152, 17181920, 479839479840,
> >552587148319552587148320
> >
> >Obviously, a(2) and the following terms are wrong.
> >I think we should have:
> >   a(2)=12
> >   a(3)=456
> >   a(4)=415416
> >   a(5)=194191194192
> >   a(6)=3816727961538167279616
> >   a(7)=35270249819024056401913527024981902405640192
> >   ...
> >
> >My question is: should I fix A094333 or should I submit an new sequence ?
> >
> >Regards,
> >
> >Paul
> >-----------------------------------------------------
> >Mail.be, WebMail and Virtual Office
> >http://www.mail.be
> >
> >_______________________________________________
> >
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>
>
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