[seqfan] Re: 2*n^2 - p(n) = k^2 ?

W. Edwin Clark wclark at mail.usf.edu
Fri Jul 26 00:29:51 CEST 2013


On Wed, Jul 24, 2013 at 10:18 PM, юрий герасимов <2stepan at rambler.ru> wrote:

>
> Hello, SegFans,
>
> Prime(n) such that 2*n^2 - prime(n) is square:
>
> 2, 7, 17, 71,...
>
> What is the next one ?
>
>
The values of prime(n) with this property up to 6*10^6 are

2, 7, 17, 71, 6607, 15313, 91801, 141689, 443777, 858463, 1353593, 2345479



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