[seqfan] Re: Formula in A060294.
Paul D Hanna
pauldhanna at juno.com
Sun Mar 24 01:36:23 CET 2013
Here is the correction to the poorly written formula:
2/Pi = 1 - 5(1/2)^3 + 9((1*3)/(2*4))^3 - 13((1*3*5)/(2*4*6))^3 ...
That is,
2/Pi = Sum_{n>0} (-1)^n * (4*n+1) * Product_{k=1..n} (2*k-1)^3/(2*k)^3. Paul
---------- Original Message ----------
From: "L. Edson Jeffery" <lejeffery2 at gmail.com>
To: seqfan at list.seqfan.eu
Subject: [seqfan] Formula in A060294.
Date: Sat, 23 Mar 2013 16:00:02 -0500
The series in A060294 for 2/Pi given by Earls in the formula section is
wrong. I searched for the correct series but could not find it. Can someone
please figure this out and fix the formula (or replace it with new one)?
Ed Jeffery
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