[seqfan] Re: a(n+1) is the multiple of at least one digit of a(n)
Hans Havermann
gladhobo at teksavvy.com
Wed May 29 14:54:23 CEST 2013
Likely an infinite number of conjectures because of the fractal-like nature of the sequence where at each successive power of ten, new "detail" emerges. I had grabbed the most blatant one.
On May 29, 2013, at 5:53 AM, Lars Blomberg <lars.blomberg at visit.se> wrote:
> ...several other conjectures where a(k)==k, can be made:
>
> - m*10^n, n >= 0, m=19,127..199,217..220,1012,1063..1999
> - 12*10^n + a, n >=1, a=7,8,9
> - m*10^n + a, n >=1, m=13..19, a=0..9
> - 22*10^n, n >= 1
> - m*10^n + a, n >=2, m=11..19, a=0..99
> and probably many more.
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