[seqfan] Re: More terms for A225053: Second terms of continued fractions for power towers e, e^e, e^e^e, ...

[Georgi Guninski]

On Mon, Apr 29, 2013 at 03:52:09PM -0700, Vladimir Reshetnikov wrote:
> Dear SeqFans,
> 
> I am looking for ideas how to calculate more terms for
> A225053<http://oeis.org/A225053>
> .
> Particularly, is it feasible to determine at least a(5) =
> floor(1/frac(e^e^e^e^e))?
> 

In mrob's hypercalc:

C2 = e^e^e^e^e;
R2 = 10 ^ ( 1.01255953 x 10 ^ 1656520 )


> And it would be a delightful surprise if e^e^e^e^e turned out to be an
> integer  :-)
> 
> --
> Thanks
> Vladimir Reshetnikov
> 
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