[seqfan] Re: a(n+1) is the multiple of at least one digit of a(n)

Eric Angelini Eric.Angelini at kntv.be
Tue May 28 23:42:36 CEST 2013


Agree, Hans, well thought !
Best,
É.

Propulsé d'un aPhone



Le 28 mai 2013 à 21:04, "Hans Havermann" <gladhobo at teksavvy.com> a écrit :

> Conjecture: For nonnegative integer n, 2*10^n appears at index 2*10^n.
> 
> 
> On May 28, 2013, at 10:46 AM, Eric Angelini <Eric.Angelini at kntv.be> wrote:
> 
>> I guess this is a permutation of the Naturals:
>> 
>> a(n+1) is the smallest integer not yet in the sequence such that
>> a(n+1) is the multiple of at least one digit of a(n):
>> 
>> S=1,2,4,8,16,3,6,12,5,10,7,14,9,18,11,13,15,17,19,20,22,24,...
> 
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