[seqfan] Re: Matrix sequence

Max Alekseyev maxale at gmail.com
Sat Nov 30 07:54:00 CET 2013


Formula for the n-th term in PARI notation:

a(n) = sum(k=0,n-1, n^k * abs( stirling(n,n-k) * stirling(n+1,k+1) ) *
(n-k)! * k! )

I also confirm that a(4) = 55456.

Regards,
Max

On Sat, Nov 30, 2013 at 12:02 AM,  <franktaw at netscape.net> wrote:
> What is the permanent of the matrix:
>
> 1 2 ... n
> n+1 n+2 ... 2n
> ...
> n^2-n+1 n^2-n+2 ... n^2  ?
>
> The sequence appears to start
>
> 1,10,450,55128
>
> from n-1; this is not in the database. (These were hand-calculated.)
>
> Franklin T. Adams-Watters
>
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