[seqfan] A230044 question
davidwwilson at comcast.net
Thu Oct 24 03:59:15 CEST 2013
It is already conjectured that A064784 has the range A230044.
For n >= 0, define
f(n) = 2*t(n) - t(m)
Where t(n) = A000217(n) is the nth triangular number, and t(m) is the
largest triangular number <= 2*t(n).
This sequence begins
f = 0,1,0,2,5,2,6,1,6,12,5,12,3,11,0,9,19,6,17,2,14,...
which does not appear to be in the OEIS.
I would conjecture that f has the same range A230044.
>From playing around with these sorts of numbers, I am inclined to think the
conjectures are true, and provable, but somewhat beyond my capabilities.
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