[seqfan] Re: A181376

Charles Greathouse charles.greathouse at case.edu
Wed Oct 16 18:58:22 CEST 2013


I think you're double-counting 1729 and 4104 for a(4) and 13832, 20683,
32832, 39312, 40033, 46683, 64232, 65728 for a(5). 1729 = 10^3+9^3 =
12^3+1^3, for example.

Charles Greathouse
Analyst/Programmer
Case Western Reserve University


On Wed, Oct 16, 2013 at 11:25 AM, Harvey P. Dale <hpd at hpdale.org> wrote:

>         I get a(4)=163 and a(5)=744.  Am I in error or are those two terms
> of the sequence in error?
>         Best,
>         Harvey
>
>
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