[seqfan] Re: A181376
Charles Greathouse
charles.greathouse at case.edu
Wed Oct 16 18:58:22 CEST 2013
I think you're double-counting 1729 and 4104 for a(4) and 13832, 20683,
32832, 39312, 40033, 46683, 64232, 65728 for a(5). 1729 = 10^3+9^3 =
12^3+1^3, for example.
Charles Greathouse
Analyst/Programmer
Case Western Reserve University
On Wed, Oct 16, 2013 at 11:25 AM, Harvey P. Dale <hpd at hpdale.org> wrote:
> I get a(4)=163 and a(5)=744. Am I in error or are those two terms
> of the sequence in error?
> Best,
> Harvey
>
>
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