[seqfan] Re: Sliding digit sums

[Eric Angelini]

Yes, Lars, my apologizes, I thought
S was somehow escaping that loop --
my mistake :-((
Best,
É.
(what about other starts ? -- I guess
whatever start, the loop is inevitable)

> Le 20 avr. 2014 à 19:02, "Lars Blomberg" <lars.blomberg at visit.se> a écrit :
> 
> I find:
> 
> S = 1,1,2,4,8,16,23,(12,6,21,3)...
> 
> Regards
> Lars B
> 
> -----Ursprungligt meddelande----- 
> From: Eric Angelini
> Sent: Sunday, April 20, 2014 6:23 PM
> To: Sequence Discussion list
> Subject: [seqfan] Sliding digit sums
> 
> 
> Hello SeqFans,
> Does S loop?
> Start S with 1.
> Now a(n) is the sum of the last "k" digits of S, "k" being the last digit of 
> S augmented by 1.
> 
> S=1,1,2,4,8,16,23,12,6,21,3,12,6,15,15,18,29,...
> 
> Example:
> S=1,... k=1+1=2; a(2)=0+1=1
> S=1,1,... k=1+1=2; a(3)=1+1=2
> S=1,1,2,... k=2+1=3; a(4)=1+1+2=4
> S=1,1,2,4,... k=4+1=5; a(5)=0+1+1+2+4=8
> S=1,1,2,4,8,... k=8+1=9; a(6)=0+1+1+2+4+8=16
> S=1,1,2,4,8,16,... k=6+1=7; a(7)=1+1+2+4+8+1+6=23
> S=1,1,2,4,8,16,23,... k=3+1=4; a(8)=1+6+2+3=12
> S=1,1,2,4,8,16,23,12,... k=2+1=3; a(9)=3+1+2=6
> S=1,1,2,4,8,16,23,12,6,... k=6+1=7; a(10)=1+6+2+3+1+2+6=21
> S=1,1,2,4,8,16,23,12,6,21,... k=1+1=2, etc.
> 
> Best,
> É.
> 
> 
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