[seqfan] Pi = cumulative sum k of a(n) digits

[Eric Angelini]

Hello SeqFans,
I cannot compute enough terms of P to check if this is old hat :-(
Say k is the cumulative sum of the first n digits of Pi's decimal
expansion (here http://oeis.org/A000796 );

a(1)=1
... because the cumulative sum k of the first « 1 » decimals of Pi is = 3
a(2)=8
... because the cumulative sum k of the first « 8 » decimals of Pi is = 31
   (3+1+4+1+5+9+2+6=31)
a(3)=0
... because _there is no n_ such that the cumulative sum k such is = 314
a(4)=0
... because _there is no n_ such that the cumulative sum k such is = 3141
Etc.
So, up to now (if I'm not wrong): P = 1, 8, 0, 0, ...

Best,
É.