[seqfan] Re: Onwards a(n) = a(n-1) + first digit of a(n)

[Hans Havermann]

> S=0,9,10,11,12,13,14,15,16,17,18,20,22,24,26,28,31,34,37,41,45,49,54,60,66,73,81,90,99,100,101,102,...
> Is it possible to compute an infinite S onwards, starting with 0 ...

Sure. One may posit multiple successors but as we reach 10^n, only that value survives.

10^1 @ 3
10^2 @ 30
10^3 @ 312
10^4 @ 3140
10^5 @ 31429
10^6 @ 314325
10^7 @ 3143292
10^8 @ 31432974
10^9 @ 314329799
...