[seqfan] Re: Sum n/prime(n)^2

[Neil Sloane]

I believe Charles's calculation of 1.1490642..., rather than the 1.106...
value, since the remainder clearly cannot be ignored.  Also, I asked David
Broadhurst,
who had calculated A115563, and he did a quick calculation and got 1.14906.

So I propose to put Charles's value as the new value,
so as not to leave the erroneous version in place any longer.

Charles, will you polish the entry when you get more terms, or a better
bound on the error?


Best regards
Neil

Neil J. A. Sloane, President, OEIS Foundation.
11 South Adelaide Avenue, Highland Park, NJ 08904, USA.
Also Visiting Scientist, Math. Dept., Rutgers University, Piscataway, NJ.
Phone: 732 828 6098; home page: http://NeilSloane.com
Email: njasloane at gmail.com


On Thu, Dec 4, 2014 at 8:05 PM, Hans Havermann <gladhobo at teksavvy.com>
wrote:

> Charles Greathouse:
>
> > a summation of the primes up to 10^10
> > 1.10463086777...
>
> Here are five partial sums up to 1.25*10^9 primes (<=28794583627):
>
> 0.25*10^9   1.1033540385172011
> 0.50*10^9   1.1048250449450470
> 0.75*10^9   1.1056413954631700
> 1.00*10^9   1.1062021315695429
> 1.25*10^9   1.1066269604122258
>
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