[seqfan] Re: The number of orbits of triples of (1, 2, ..., n) under the action of the dihedral group of order 2n

[W. Edwin Clark]

Ed,

That's certainly the case if you believe Collin Barker's conjectured
formula:

 a(n) = (5+3*(-1)^n+2*n^2)/4  (See the history of A236283
<https://oeis.org/A236283>)

For if true then

   a(2n) = 2+2n^2 A005893 <http://oeis.org/A005893>
   a(2n+1) = 2n^2+2n+1 A001844

<http://oeis.org/A001844>A strange connection!  How did you arrive at this?

Edwin





On Tue, Jan 21, 2014 at 3:17 PM, L. Edson Jeffery <lejeffery2 at gmail.com>wrote:

> Edwin, your A236283 looks like A001844 union A005893.
>
> Ed Jeffery
>
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