[seqfan] Prime partionable numbers and {P1} and {P2}.
Chris
cgribble263 at btinternet.com
Thu Jul 10 20:18:25 CEST 2014
Dear Seqfans,
W. Holsztynski, R. F. E. Strube, Paths and circuits in finite groups, Discr.
Math. 22 (1978) 263-272,
Definition 5.3 on Page 269, defines a prime-partitionable number as follows:
"An integer n>=2 is said to be prime-partitionable if there is a partition
{P1,P2} of the set P of all
primes less than n such that, for all natural numbers n1 and n2 satisfying
n1+n2=n, we have
(gcd (nl, pl), gcd (n2, p2)) does not equal (1,1) for some (p1,p2) belonging
to PI X P2."
The first prime-partitionable number is 16. The set of primes < 16 = {2, 3,
5, 7, 11, 13}.
There are two partitions of P that demonstrate that 16 is
prime-partitionable, denoted by Pt1 and Pt2:
Pt1: P1 = {2, 5, 11}, P2 = {3, 7, 13}
Pt2: P1 = {2, 3, 7, 13}, P2 = {5, 11}
Pt1 Pt2
n1 n2 p1 p2 p1 p2
1 + 15 - 3 - 5
2 + 14 2 7 2 -
3 + 13 - 13 3 -
4 + 12 2 3 2 -
5 + 11 5 - - 11
6 + 10 2 - 2 5
7 + 9 - 3 7 -
8 + 8 2 - 2 -
9 + 7 - 7 3 -
10 + 6 2 3 2 -
11 + 5 11 - - 5
12 + 4 2 - 2 -
13 + 3 - 3 13 -
14 + 2 2 - 2 -
15 + 1 5 - 3 -
For each n1+n2, either p1|n1 or p2|n2 or both.
I have determined all partitions of P that demonstrate that n is
prime-partitionable for n in
{16, 22, 34, 36, 46, 56, 64, 66, 70, 76, 78, 86, 88, 92, 94, 96} and have
noticed that each P1 and
each P2 contains one or more prime partitions of n, e.g. in P1 of Pt1,
5+11=16; in P2 of Pt1, 3+13=16;
in P1 of Pt2, 3+13=16; in P2 of Pt2, 5+11=16.
Is this generally true? Can someone explain it?
Best regards,
Chris Gribble
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