[seqfan] Re: A115491

[Bruno Berselli]

Yes, I agree with Franklin.

Bruno


Il Venerdì 25 Luglio 2014 16:40, Frank Adams-Watters <franktaw at netscape.net> ha scritto:
 


The formula that is off by 1 should be fixed. The simplest fix is to 
just change it to "a(n+1) = ...".

Franklin T. Adams-Watters


-----Original Message-----
From: Bruno Berselli <berselli.bruno at yahoo.it>

Robert, Paolo has stated that his formula is valid for n>= 0. In my 
opinion we
can keep both versions (this has happened many times in OEIS).

Bruno


Il Venerdì 25 Luglio 2014 9:44, "israel at math.ubc.ca" 
<israel at math.ubc.ca> ha
scritto:

I see some changes to A115491 have just been published.  There are now 
two
competing formulas for a(n):

a(n) = -(2/5)*2^n+(32/5)*32^n, with n>=0. - _Paolo P. Lava_, Jun 17 
2008

a(n) = (32^(n+1)-16*2^(n+1))/160. - _Vincenzo Librandi_, Jul 25 2014

Vincenzo's agrees with the data (note that a(1) = 6), but
Paolo's is for a(n+1), not a(n): he has a(1) = 204.
So, what to do? 


Cheers,
Robert

  

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