[seqfan] Re: a(n) divides the sum of the first a(n) terms of T.
franktaw at netscape.net
Thu Jun 12 05:03:37 CEST 2014
Right. I needed to say k > n instead of >=.
Franklin T. Adams-Watters
From: Max Alekseyev <maxale at gmail.com>
To: Sequence Fanatics Discussion list <seqfan at list.seqfan.eu>
Sent: Wed, Jun 11, 2014 9:58 pm
Subject: [seqfan] Re: a(n) divides the sum of the first a(n) terms of T.
On Wed, Jun 11, 2014 at 9:59 PM, Frank Adams-Watters
<franktaw at netscape.net> wrote:
> Once you have a k such that k >= n and a(k) > n, n can no longer
> the sequence; otherwise a(k) would be n.
Take n = 2 and k = 2. We have a(k) = 3 > n, but n still appears in the
sequence as a(3).
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