[seqfan] Re: a(n) divides the sum of the first a(n) terms of T.
Neil Sloane
njasloane at gmail.com
Thu Jun 12 20:57:51 CEST 2014
It looks like no one has submitted this.
It is hard to be sure, there are over 100 seqs on the stack.
Has anyone here submitted it? If not, I will do it at half-time
On Wed, Jun 11, 2014 at 11:03 PM, Frank Adams-Watters <franktaw at netscape.net
> wrote:
> Right. I needed to say k > n instead of >=.
>
>
> Franklin T. Adams-Watters
>
> -----Original Message-----
> From: Max Alekseyev <maxale at gmail.com>
> To: Sequence Fanatics Discussion list <seqfan at list.seqfan.eu>
> Sent: Wed, Jun 11, 2014 9:58 pm
> Subject: [seqfan] Re: a(n) divides the sum of the first a(n) terms of T.
>
>
> On Wed, Jun 11, 2014 at 9:59 PM, Frank Adams-Watters
> <franktaw at netscape.net> wrote:
>
>> Once you have a k such that k >= n and a(k) > n, n can no longer
>>
> appear in
>
>> the sequence; otherwise a(k) would be n.
>>
>
> Take n = 2 and k = 2. We have a(k) = 3 > n, but n still appears in the
> sequence as a(3).
>
> Regards,
> Max
>
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--
Dear Friends, I have now retired from AT&T. New coordinates:
Neil J. A. Sloane, President, OEIS Foundation
11 South Adelaide Avenue, Highland Park, NJ 08904, USA.
Also Visiting Scientist, Math. Dept., Rutgers University, Piscataway, NJ.
Phone: 732 828 6098; home page: http://NeilSloane.com
Email: njasloane at gmail.com
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