[seqfan] Re: a(n) divides the sum of the first a(n) terms of T.

[Neil Sloane]

It looks like no one has submitted this.

It is hard to be sure, there are over 100 seqs on the stack.

Has anyone here submitted it? If not, I will do it at half-time


On Wed, Jun 11, 2014 at 11:03 PM, Frank Adams-Watters <franktaw at netscape.net
> wrote:

> Right. I needed to say k > n instead of >=.
>
>
> Franklin T. Adams-Watters
>
> -----Original Message-----
> From: Max Alekseyev <maxale at gmail.com>
> To: Sequence Fanatics Discussion list <seqfan at list.seqfan.eu>
> Sent: Wed, Jun 11, 2014 9:58 pm
> Subject: [seqfan] Re: a(n) divides the sum of the first a(n) terms of T.
>
>
> On Wed, Jun 11, 2014 at 9:59 PM, Frank Adams-Watters
> <franktaw at netscape.net> wrote:
>
>> Once you have a k such that k >= n and a(k) > n, n can no longer
>>
> appear in
>
>> the sequence; otherwise a(k) would be n.
>>
>
> Take n = 2 and k = 2. We have a(k) = 3 > n, but n still appears in the
> sequence as a(3).
>
> Regards,
> Max
>
> _______________________________________________
>
> Seqfan Mailing list - http://list.seqfan.eu/
>
>
>
> _______________________________________________
>
> Seqfan Mailing list - http://list.seqfan.eu/
>



-- 
Dear Friends, I have now retired from AT&T. New coordinates:

Neil J. A. Sloane, President, OEIS Foundation
11 South Adelaide Avenue, Highland Park, NJ 08904, USA.
Also Visiting Scientist, Math. Dept., Rutgers University, Piscataway, NJ.
Phone: 732 828 6098; home page: http://NeilSloane.com
Email: njasloane at gmail.com