[seqfan] Re: need help for a calculation

[Frank Adams-Watters]

You computed right up to where they diverge.  floor(3/2)^17) = 985 has 
10 digits, but A005378(17) = 11. Sorry.

Franklin T. Adams-Watters

-----Original Message-----
From: David Newman <davidsnewman at gmail.com>
To: Sequence Fanatics Discussion list <seqfan at list.seqfan.eu>
Sent: Sat, Jun 28, 2014 1:42 pm
Subject: [seqfan] need help for a calculation


I'm away from home and don't have access to my copy of Mathematica,
otherwise I'd do this myself.

How many binary digits are there in Floor [ (3/2) ^n ] ?

The first 16 values that I've computed by hand seem to agree with 
A005378.

ex. for n=0    Floor[ (3/2)^0]=1  which is 1 in binary, so a(0)=1

for n=1  Floor[3/2]=1, which is 1 in binary, so a(1)=1

for n=2  Floor[9/4]=2, which is 10 in binary, so a(2)=2

I'd be very pleasantly surprised if this continues since the quantity 
being
calculated is related to several unsolved problems.

If anyone out there has a few minutes to continue the calculations I'd
appreciate it.

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