[seqfan] Re: New formula for A030101 ?

[Aai]

If I'm not wrong, acc. to PE 463 term

f(4n+3)=3f(2n+1) + 2f(n)

should be

f(4n+3)=3f(2n+1) - 2f(n)



On 16-03-14 12:42, Martin Møller Skarbiniks Pedersen wrote:
>    It looks like the sequences A030101 and f(x) in Euler Problem 463 are the
> same but I am
> not sure.
>
>    A030101: a(n) is the number produced when n is converted to base 2,
> reversed and then converted back to base 10.
>
>    Euler Problem 463:
>      f(1)=1, f(3)=3, f(2n)=f(n), f(4n+1)=2f(2n+1)-f(n),
> f(4n+3)=3f(2n+1)+2f(n)
>
> Regards
> Martin M. S. Pedersen
>
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