[seqfan] Re: Modular Partitions
Chris
cgribble263 at btinternet.com
Fri May 2 14:09:29 CEST 2014
It appears that T(n, k) = (n + k - 1)! / (k! * n!) for all n == +-1 mod k, k > 1.
In addition, it appears that
T(n, 2) = ((n + 1) + 1) / 2!, n == 0 mod 2 (A000012)
T(n, 3) = ((n + 2)(n + 1) + 4) / 3!, n == 0 mod 3 (A007997)
T(n, 4) = ((n + 3)(n + 2)(n + 1) + 3 * (n + 6)) / 4!, n == 0 mod 4; ((n + 3)(n + 2)(n + 1) + 3 * (n + 2)) / 4!, n == 2 mod 4 (A008610)
T(n, 5) = ((n + 4)(n + 3)(n + 2)(n + 1) + 96) / 5!, n == 0 mod 5; (n + 4)(n + 3)(n + 2)(n + 1) / 5!, n == 2:3 mod 5 (A008646)
Conjecture: For p prime,
T(n, p) = (n + p - 1)! / (p! * n!) for n !== 0 mod p.
T(n, p) = (n + p - 1)! / (p! * n!) + (p - 1) / p for n == 0 mod p.
Best regards,
Chris Gribble
-----Original Message-----
From: SeqFan [mailto:seqfan-bounces at list.seqfan.eu] On Behalf Of Jens Voß
Sent: 30 April 2014 20:19
To: Sequence Fanatics Discussion list
Subject: [seqfan] Modular Partitions
Hi there, sequence fans,
I was playing around with what I call "modular partition numbers":
Essentially different ways to write the neutral element of the group Z/nZ as a sum of length k (for given n, k > 0).
For example, for n = 5 and k = 4, we have thepartitions
0+0+0+0 = 0
0+0+1+4 = 5 = 0
0+0+2+3 = 5 = 0
0+1+1+3 = 5 = 0
0+1+2+2 = 5 = 0
0+2+4+4 = 10 = 0
0+3+3+4 = 10 = 0
1+2+3+4 = 10 = 0
1+3+3+3 = 10 = 0
3+4+4+4 = 15 = 0
so the number of 5-modular partitions of length 4 is 10.
I computed the the values for n + k < 20 (as a square array read by antidiagonals), and was somewhat surprised that this sequence isn't yet in the database (even though several of the rows resp. columns are).
However, I was even more surprised to find that the array is symmetric in n and k:
1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
1 1 1 1
1 2 2 3 3 4 4 5 5 6 6 7 7 8 8
9 9 10
1 2 4 5 7 10 12 15 19 22 26 31 35 40 46
51 57
1 3 5 10 14 22 30 43 55 73 91 116 140 172 204 245
1 3 7 14 26 42 66 99 143 201 273 364 476 612 776
1 4 10 22 42 80 132 217 335 504 728 1038 1428 1944
1 4 12 30 66 132 246 429 715 1144 1768 2652 3876
1 5 15 43 99 217 429 810 1430 2438 3978 6310
1 5 19 55 143 335 715 1430 2704 4862 8398
1 6 22 73 201 504 1144 2438 4862 9252
1 6 26 91 273 728 1768 3978 8398
1 7 31 116 364 1038 2652 6310
1 7 35 140 476 1428 3876
1 8 40 172 612 1944
1 8 46 204 776
1 9 51 245
1 9 57
1 10
1
I haven't been able to come up with a formula for the numbers (neither recursive nor direct), and I don't see an immediate reason for the symmetry either (some sort of dualism). Can somebody find a formula or explain why the array is symmetric?
Best regards,
Jens
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