[seqfan] Re: Conjecture on A167055 Numbers n such that 12*n + 5 is prime.

[Tw Mike]

You are right. At last the question becomes this:
Let A={n | 2n+1 in P}, let B be the set of the sum of every two items of
A,then B={n in Z | n>1}.This is equivalent to every even integer greater
than 4 can be expressed as the sum of two primes.

Yours mike,


2014-05-20 0:27 GMT+08:00 <franktaw at netscape.net>:

> This is very similar to the Goldbach conjecture, and probably just as
> difficult.
>
> Franklin T. Adams-Watters
>
>
> -----Original Message-----
> From: Tw Mike <mt.kongtong at gmail.com>
> To: Sequence Fanatics Discussion list <seqfan at list.seqfan.eu>
> Sent: Mon, May 19, 2014 10:52 am
> Subject: [seqfan] Conjecture on A167055 Numbers n such that 12*n + 5 is
> prime.
>
>
> Dear seqfans,
>
> 0, 1, 2, 3, 4, 7, 8, 9, 11, 12, 14, 16, 19, 21,... are itmes of  A167055.
> I conjecture that the set of  the sum of every  two items of this seq is
> the set of nonnegative Integers.i.e.:0+0=0,0+1=1,...,1+4=5,...
>
> Further information for A167055:
> A167055 nonnegative integers  that not of the following two forms:
>
> 3*x^2+(6*y−3)*x+y−1
> 3*x^2+(6*y−3)*x−y , x,y in Z+.
>
> Yours mike,
>
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