[seqfan] Re: Wajnberg variations (100 terms and percentages)
acwacw at gmail.com
Thu Oct 2 17:26:43 CEST 2014
I think I am not really understanding the rules.
Let us abbreviate a sequence of n n's, then m m's, and so on, as [n,m...];
for example, "2,2,3,3,3" would be written "[2,3]".
Then Eric's S% is [1,2,3,4,6,7,8,9,10,11,12,13,14]; T% =
[1,4,5,6,7,8,9,10,11,12,13,14]; U% = [2,3,5,6,7,8,9,10,11,12,13,14]. Then
he says that these are the only such 100-sequences. What is wrong with,
say, [1,99]? Or [4,5,6,12,30,43]? What additional constraint is there
besides that it must be a partition of 100 into blocks of distinct sizes?
On Thu, Oct 2, 2014 at 6:16 AM, Eric Angelini <Eric.Angelini at kntv.be> wrote:
> Hello SeqFans,
> here are 3 seq I've discussed with my friend Alexandre W.
> S%, T% and U% are 3 finite seq of 100 terms each.
> They self-describe their content in a "percentage way":
> S% =
> T% =
> U% =
> Explanation (for U%, immediately above):
> Among the 100 terms of U%, only two are '2' --> there is 2% of '2'
> Among the 100 terms of U%, only three are '3' --> there is 3% of '3'
> Among the 100 terms of U%, only five are '5' --> there is 5% of '5'
> Among the 100 terms of U%, only six are '6' --> there is 6% of '6'
> Among the 100 terms of U%, only fourteen are '14' --> there is 14% of '14'
> Those are the only such 100-term possible seq -- and S% is the
> lexically first (then T%, then U%).
> A 1000-term such seq is easy to build. And a 10,000 one also, etc.
> But is it possible to build an infinite seq like that? Well, there
> is at least this one : H% = 100,100,100,100,100,100,100,100,...
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