[seqfan] Re: Cumulative sum of the digits used so far
Eric Angelini
Eric.Angelini at kntv.be
Thu Oct 30 09:10:10 CET 2014
I guess a(1) should be = 0
Catapulté de mon aPhone
> Le 30 oct. 2014 à 08:22, "Eric Angelini" <Eric.Angelini at kntv.be> a écrit :
>
>
> Hello SeqFans,
> I think this is the beginning of the
> slowest ever-increasing sequence
> where a(n) is the sum of the digits
> present so far in the sequence,
> including the digits of a(n):
>
> 9, 18, 27, 36, 45, 54, 63, 72, 81, 99,
> 108, 117, 126, 135, 144, 153, 162,
> 171, 180, 198, 207, 216, 225, 234,
> 243, 252, 261, 279, 297, 306, 315,
> 324, 333, 342, 351, 360, 378, 396,
> 405, 414, 423, 432, 441, ...
>
> I'm not sure, though, because you
> have usually gaps of 9 units between
> two consecutive terms, and sometimes
> gaps of 18 units... I don't know how
> to handle algorithmically those.
>
> Best,
> É.
>
>
>
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