[seqfan] Re: Confused by Collatz-Fibonacci numbers
Eric Schmidt
eric41293 at comcast.net
Fri Apr 3 05:22:26 CEST 2015
On 4/2/2015 8:48 PM, Alonso Del Arte wrote:
> I'm still perplexed by the Collatz-Fibonacci numbers, A174429. By Tony's
> formula from 2010, I get a(3) = 21. But by the formula in the title, I get
> a(3) = 60. Maybe I've made some simple mistake of arithmetic or logic. Can
> someone take a look to see if they don't or if they also see an
> inconsistency?
For me the formula in the title agrees with the given terms, including
a(3) = 21. I used the following Sage code.
def collatz(n) :
if n%2==0 : return n//2
return 3*n+1
def a(n) :
if n==1 or n==2 : return 1
return a(collatz(n)) + a(collatz(collatz(n)))
I get the same results from Tony's formula.
--
Eric Schmidt
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