[seqfan] Re: Cumulative multiplication

Giovanni Resta g.resta at iit.cnr.it
Wed Apr 29 16:04:38 CEST 2015


On 04/19/2015 05:15 AM, David Wilson wrote:
> I would be very surprised if we found any more good numbers.

Isn't it nice when life surprises us ?

3682784876146817236992 = p(3682784876146817236992) * p(3682784876).


(No other < 10^100. If we allow to multiply digits from both ends
of the number, like in
4794391461888 = 8*8*8*(4*7*9*4*3*9*1*4*6*1*8*8*8)*4*7, then the
non trivial such numbers < 10^100 are
128, 175, 384, 735, 1296, 18432, 34992, 442368, 4128768, 13395375,
13436928, 161243136, 1269789696, 4161798144, 149824733184,
611784327168, 4794391461888, 2877833474998272, 3682784876146817236992.)

Giovanni




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