[seqfan] Re: Question about submission guidelines

Brad Klee bradklee at gmail.com
Thu Aug 20 22:16:12 CEST 2015


Hi Vladimir,

Your approach also seems good, but requires three recurrence definitions as opposed to two.

If you want to involve Fibonacci, it may be worthwhile to look into the irrational quantity:

n x^n

Where x is the golden ratio.

Best,

Brad

> On Aug 20, 2015, at 3:49 AM, Vladimir Shevelev <shevelev at bgu.ac.il> wrote:
> 
> Hi Bob and Brad,
> 
> Here is quite simple proof.
> Note that F_1=F(n+1)+F(n-1)=L(n), n>=1.
> Indeed, L(1)=F_1(1)=1, L(2)=F_1(2)=3,
> and trivially F_1(n-1)+F_1(n-2)=F_1(n).
> 
> So  F(n)=L(n-1)-F(n-2). Let us add to this an equality
> nF(n)=nF(n-1)+nF(n-2). So, 
> a(n)=a(n-1)+a(n-2)+L(n-1).
> 
> Best regards,
> Vladimir
> ________________________________________
> From: SeqFan [seqfan-bounces at list.seqfan.eu] on behalf of Brad Klee [bradklee at gmail.com]
> Sent: 20 August 2015 01:02
> To: Sequence Fanatics Discussion list
> Subject: [seqfan] Re: Question about submission guidelines
> 
> Hi Bob,
> 
> I found your relation interesting to prove. It requires some manipulation
> of the connection between recurrence equations. Using "a" for A099920 and
> "L" for A000032 you give
> 
> a(n) = a(n-1) + a(n-2) + L(n-1),          (1)
> 
> or
> 
> L(n-1) = a(n) - a(n-1) - a(n-2).            (2)
> 
> This is a functional definition for L(n) which may or may not be true. By
> the recurrence definition for a(n),
> 
> L(n-1) = a(n-1) - 2 a(n-3) - a(n-4),
> L(n) = a(n) - 2 a(n-2) - a(n-3).               (3)
> 
> These functions match on a few terms, but do they match on all terms?
> Since the Axiom is fine, we just need to check satisfaction of the
> recurrence relations. Combining 1 and 3 by the recurrence definition for
> L(n)
> 
> L(n+1) ?= L(n) +L(n-1),
> L(n+1) ?= 2 a(n) - a(n-1) - 3 a(n-2) - a(n-3).  (4)
> 
> By incrementing Eq. 3
> 
> L(n+1) = a(n+1) - 2 a(n-1) - a(n-2).  (5)
> 
> Subtracting Eq. 5,4
> 
> 0 ?= a(n+1) - 2 a(n) - a(n-1) + 2 a(n-2) + a(n-3).
> 
> According to the recurrence definition of a(n), the equality is satisfied.
> Then the definition of L(n) is proven true.
> 
> This logic affords a production system. We can iterate the recurrence
> relations for L(n) to produce an infinite number of equalities that relate
> L(n+k) to the four values { a(n), a(n-1), a(n-2), a(n-3) }.
> 
> Eq.3 is a nice complement to Eq. 2. Maybe that equation should also be
> added.
> 
> Cheers,
> 
> Brad
> 
> 
> 
> On Wed, Aug 19, 2015 at 12:43 PM, Alonso Del Arte <alonso.delarte at gmail.com>
> wrote:
> 
>> My two cents: if it's important enough for you to write a letter of more
>> than a hundred words to SeqFan about it, it's important enough to submit
>> even now.
>> 
>> Al
>> 
>>> On Wed, Aug 19, 2015 at 1:01 PM, Neil Sloane <njasloane at gmail.com> wrote:
>>> 
>>> sure, post it!
>>> 
>>> Best regards
>>> Neil
>>> 
>>> Neil J. A. Sloane, President, OEIS Foundation.
>>> 11 South Adelaide Avenue, Highland Park, NJ 08904, USA.
>>> Also Visiting Scientist, Math. Dept., Rutgers University, Piscataway, NJ.
>>> Phone: 732 828 6098; home page: http://NeilSloane.com
>>> Email: njasloane at gmail.com
>>> 
>>> 
>>> On Wed, Aug 19, 2015 at 10:47 AM, Bob Selcoe <rselcoe at entouchonline.net>
>>> wrote:
>>> 
>>>> (Hi Olivier - no worries if you would rather reply to me individually
>>> than
>>>> post this to the general discussion board)
>>>> 
>>>> Hello Seqfans,
>>>> 
>>>> I was hoping some of the more seasoned contributors might be able to
>>>> provide a little guidance on what (and what not) to post, given the
>>>> impacted submission stack.
>>>> 
>>>> For example, I was intending to contribute a very simple formula for
>>>> A099920 (Fibonacci-Lucas convolution): a(n) = a(n-1) + a(n-2) +
>>>> A000032(n-1) (Lucas numbers).
>>>> 
>>>> Though this one isn't earth-shattering, it still seems to me that any
>>>> simple formula for a sequence involving other core sequences might be
>>>> useful, and easy to review.
>>>> 
>>>> But I'm reluctant to post it under the current circumstances;
>> especially
>>>> since I have 3 proposed submissions already under review, including a
>> new
>>>> sequence posted 7 weeks ago with substantial activity on it.
>>>> 
>>>> So, are these types of submissions still OK?  Any rules-of-thumb to
>> keep
>>>> in mind before offering any more contributions?
>>>> 
>>>> Thanks,
>>>> Bob Selcoe
>>>> 
>>>> _______________________________________________
>>>> 
>>>> Seqfan Mailing list - http://list.seqfan.eu/
>>> 
>>> _______________________________________________
>>> 
>>> Seqfan Mailing list - http://list.seqfan.eu/
>> 
>> 
>> 
>> --
>> Alonso del Arte
>> Author at SmashWords.com
>> <https://www.smashwords.com/profile/view/AlonsoDelarte>
>> Musician at ReverbNation.com <http://www.reverbnation.com/alonsodelarte>
>> 
>> _______________________________________________
>> 
>> Seqfan Mailing list - http://list.seqfan.eu/
> 
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