# [seqfan] Re: A265182

Neil Sloane njasloane at gmail.com
Sat Dec 5 19:15:11 CET 2015

```no, you are probably right, I calculated them by hand and asked someone to
check them, saying they (meaning A265182 and A265183) were probably wrong.

Best regards
Neil

Neil J. A. Sloane, President, OEIS Foundation.
11 South Adelaide Avenue, Highland Park, NJ 08904, USA.
Also Visiting Scientist, Math. Dept., Rutgers University, Piscataway, NJ.
Email: njasloane at gmail.com

On Sat, Dec 5, 2015 at 4:02 AM, Lars Blomberg <lars.blomberg at visit.se>
wrote:

>
>
> Hello,
>
>
>
> Attempting to reproduce A265182, I get a rather different result:
>
> OEIS: 1, 0, 0, 0, 0, 0, 0, 0, 0, 3, 3, 5, 3, 3, 3, 3, 3, 3, 3, 0, 5, 0, 0,
> 1, 0, 0, 0, 0, 0, 0, 5, 0, 0, 0, 0, 0, 0, 0, 1, 0, 5
>
> Mine: 1, 0, 0, 0, 0, 0, 0, 0, 0, 3, 3, 5, 5, 5, 5, 5, 5, 5, 5, 0, 5, 0, 0,
> 1, 1, 0, 0, 0, 0, 0, 5, 0, 0, 0, 0, 1, 0, 0, 1, 0, 5
>
>
>
> For n=12 the substrings are 1,2,12 and the products  1*1=1,  1*2=2, 2*1=2,
> 1*12=12,             12*1=12.
>
> And similarly for n=13: substrings 1,3,13, products  1*1=1,  1*3=3,  3*1=3n
> 1*13=13,             13*1=13.
>
> So I find a(13)=5, not 3.
>
>
>
> And for n=25: substrings 2,5,25, product 5*5=25.
>
> So I find a(25)=1, not 0.
>
> Similar situation for n=36.
>
>
>
> Am I missing something here?
>
>
>
> /Lars B
>
>
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>
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>
```