[seqfan] a(n) divides [a(n+1)+(n+k)] General

Eric Angelini Eric.Angelini at kntv.be
Mon Dec 7 23:23:25 CET 2015

My former post could be seen as
a particular case of 
<  a(n) divides [a(n+1)+(n+k)]  >
   with k=1.

Here is the case for k=2:


(done by hand, 40 min before midnight)

If this is of interest, the seq computed
with k=1 to 10 could be entered.

(now in bed)
Catapulté de mon aPhone

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