Dear Neil, An observation. In the sequences A050476 and A253072 we have that: a(0) = 1 a(1) = 7 a(3) = 95 a(7) = 18447 A253072(2^k-1) = A050476(2^k-1), 0<=k<=m, where m is at least 3. Best regards. Omar E. Pol